![]() ![]() When the waters are mixed, the entropy _. However, the entropy change for surroundings will be less in process B because more work is done (more efficient process).ġ0 A gallon of hot water is mixed with a gallon of cold water in a perfectly insulated container. Which process has the larger entropy change for the gas? 1 2 100 kJ Process A Process B Both process have the same change in entropy of the gas 1 2 200 kJ ANSWER: C The entropy change of the fluid is the same for both processes, because entropy is a state function and is always the same in state 2. For process B, 200 kJ of work was done by the gas. For process A, 100 kJ of work was done by the gas. ∆G=∆H-T∆S and ∆H = 0.ĩ Which process has the larger entropy change for the gas?Īn ideal gas undergoes two irreversible processes between state 1 and state 2. What is most correct expression for DG? ∆H-3RTln(2) ∆H-3Rln(2) -3RTln(2) 3RTln(2) ∆H+3RTln(2) 1 atm 1 mol Ar 2 atm 2 mol O2 ANSWER: C. When the blue partition is removed between the two ideal gases below, the change is entropy is DS = 3Rln(2). Note that the partial pressure of O2 will still go down in case A, even though the pressure on the opposite side of the partition is higher. In this case, the partial pressure of each gas decreases so that the total entropy change (based on contributions from each gas) is the highest. 2 atm N2 1 atm O2 3 atm Vacuum A C ANSWER: A The N2 and O2 system. B Dħ Which of the following systems will have the largest entropy change when the blue partition is removed? The gases are ideal. ![]() N2 Vacuum O2 A C ANSWER: C In this case, the partial pressure of each gas decreases so that the total entropy change (based on contributions from each gas) is the highest. Which of the following systems will have the largest entropy change when the blue partition is removed? The ideal gases are initially at 1 atm. Adding heat to the fluid at constant pressure will raise the temperature, and higher temperature corresponds to higher entropy.Ħ The ideal gases are initially at 1 atm. Si So increases remains the same decreases Insufficient information ANSWER: A increases. As air flows through the pipe, the entropy of the air _. one that avoids gradients in pressure, must be chosen to evaluate entropy changes.ĥ Air flows steadily at constant pressure through a pipe that is heated by a furnace. The total entropy of a system plus its surroundings greater than or equal to zero, so the entropy of the surroundings must increase as the entropy of the gas decreases.Ĥ What external pressure should be used in the WEC term when calculating the entropy change for isothermal compression of an ideal gas? A constant external pressure An external pressure that is always equal to the system pressure Either (A) or (B) Neither (A) or (B) ANSWER: B An external pressure that is always equal to the system pressure. How many different ways can you do this? 4 8 12 16 None of the above ANSWER: D. You have 4 balls: red, green blue, and yellow. Falconer & Will Medlin Department of Chemical and Biological Engineering University of Colorado Boulder, CO Supported by the National Science FoundationĢ You have 4 balls: red, green blue, and yellow
0 Comments
Leave a Reply. |
Details
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |